Distance from Aleksandrow Lodzki to McKinleyville
The shortest distance (air line) between Aleksandrow Lodzki and McKinleyville is 5,660.72 mi (9,110.05 km).
How far is Aleksandrow Lodzki from McKinleyville
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 20:34 (06.12.2025)
McKinleyville is located in California, United States within 40° 56' 55.68" N -125° 54' 51.48" W (40.9488, -124.0857) coordinates. The local time in McKinleyville is 11:34 (06.12.2025)
The calculated flying distance from McKinleyville to McKinleyville is 5,660.72 miles which is equal to 9,110.05 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
McKinleyville, California, United States