Distance from Aleksandrow Lodzki to North New Hyde Park
The shortest distance (air line) between Aleksandrow Lodzki and North New Hyde Park is 4,197.38 mi (6,755.02 km).
How far is Aleksandrow Lodzki from North New Hyde Park
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 05:41 (07.12.2025)
North New Hyde Park is located in New York, United States within 40° 44' 45.6" N -74° 18' 44.64" W (40.7460, -73.6876) coordinates. The local time in North New Hyde Park is 23:41 (06.12.2025)
The calculated flying distance from North New Hyde Park to North New Hyde Park is 4,197.38 miles which is equal to 6,755.02 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
North New Hyde Park, New York, United States