Distance from Aleksandrow Lodzki to Phenix City
The shortest distance (air line) between Aleksandrow Lodzki and Phenix City is 5,042.09 mi (8,114.47 km).
How far is Aleksandrow Lodzki from Phenix City
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 02:59 (09.12.2025)
Phenix City is located in Alabama, United States within 32° 27' 30.6" N -86° 58' 28.92" W (32.4585, -85.0253) coordinates. The local time in Phenix City is 20:59 (08.12.2025)
The calculated flying distance from Phenix City to Phenix City is 5,042.09 miles which is equal to 8,114.47 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Phenix City, Alabama, United States