Distance from Aleksandrow Lodzki to Pocatello
The shortest distance (air line) between Aleksandrow Lodzki and Pocatello is 5,287.26 mi (8,509.02 km).
How far is Aleksandrow Lodzki from Pocatello
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 18:05 (10.12.2025)
Pocatello is located in Idaho, United States within 42° 52' 20.64" N -113° 32' 7.08" W (42.8724, -112.4647) coordinates. The local time in Pocatello is 10:05 (10.12.2025)
The calculated flying distance from Pocatello to Pocatello is 5,287.26 miles which is equal to 8,509.02 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Pocatello, Idaho, United States