Distance from Aleksandrow Lodzki to Pottstown
The shortest distance (air line) between Aleksandrow Lodzki and Pottstown is 4,293.92 mi (6,910.40 km).
How far is Aleksandrow Lodzki from Pottstown
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 17:32 (11.12.2025)
Pottstown is located in Pennsylvania, United States within 40° 15' 2.88" N -76° 21' 19.8" W (40.2508, -75.6445) coordinates. The local time in Pottstown is 11:32 (11.12.2025)
The calculated flying distance from Pottstown to Pottstown is 4,293.92 miles which is equal to 6,910.40 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Pottstown, Pennsylvania, United States