Distance from Aleksandrow Lodzki to Pottsville
The shortest distance (air line) between Aleksandrow Lodzki and Pottsville is 4,293.31 mi (6,909.41 km).
How far is Aleksandrow Lodzki from Pottsville
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 16:56 (11.12.2025)
Pottsville is located in Pennsylvania, United States within 40° 40' 47.28" N -77° 47' 27.24" W (40.6798, -76.2091) coordinates. The local time in Pottsville is 10:56 (11.12.2025)
The calculated flying distance from Pottsville to Pottsville is 4,293.31 miles which is equal to 6,909.41 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Pottsville, Pennsylvania, United States