Distance from Aleksandrow Lodzki to Ridgeland
The shortest distance (air line) between Aleksandrow Lodzki and Ridgeland is 5,227.47 mi (8,412.80 km).
How far is Aleksandrow Lodzki from Ridgeland
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 20:15 (11.12.2025)
Ridgeland is located in Mississippi, United States within 32° 25' 24.96" N -91° 51' 6.84" W (32.4236, -90.1481) coordinates. The local time in Ridgeland is 13:15 (11.12.2025)
The calculated flying distance from Ridgeland to Ridgeland is 5,227.47 miles which is equal to 8,412.80 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Ridgeland, Mississippi, United States