Distance from Aleksandrow Lodzki to Rive-de-Gier
The shortest distance (air line) between Aleksandrow Lodzki and Rive-de-Gier is 796.44 mi (1,281.74 km).
How far is Aleksandrow Lodzki from Rive-de-Gier
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 15:41 (03.01.2026)
Rive-de-Gier is located in Loire, France within 45° 31' 45.84" N 4° 37' 0.84" E (45.5294, 4.6169) coordinates. The local time in Rive-de-Gier is 15:41 (03.01.2026)
The calculated flying distance from Rive-de-Gier to Rive-de-Gier is 796.44 miles which is equal to 1,281.74 km.
Aleksandrow Lodzki, Łódzki, Poland