Distance from Aleksandrow Lodzki to Robertsville
The shortest distance (air line) between Aleksandrow Lodzki and Robertsville is 4,239.74 mi (6,823.20 km).
How far is Aleksandrow Lodzki from Robertsville
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 20:14 (11.12.2025)
Robertsville is located in New Jersey, United States within 40° 20' 22.2" N -75° 42' 21.96" W (40.3395, -74.2939) coordinates. The local time in Robertsville is 14:14 (11.12.2025)
The calculated flying distance from Robertsville to Robertsville is 4,239.74 miles which is equal to 6,823.20 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Robertsville, New Jersey, United States