Distance from Aleksandrow Lodzki to Robstown
The shortest distance (air line) between Aleksandrow Lodzki and Robstown is 5,748.13 mi (9,250.72 km).
How far is Aleksandrow Lodzki from Robstown
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 20:12 (11.12.2025)
Robstown is located in Texas, United States within 27° 47' 38.4" N -98° 19' 50.88" W (27.7940, -97.6692) coordinates. The local time in Robstown is 13:12 (11.12.2025)
The calculated flying distance from Robstown to Robstown is 5,748.13 miles which is equal to 9,250.72 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Robstown, Texas, United States