Distance from Aleksandrow Lodzki to Rockville Centre
The shortest distance (air line) between Aleksandrow Lodzki and Rockville Centre is 4,199.54 mi (6,758.50 km).
How far is Aleksandrow Lodzki from Rockville Centre
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 20:45 (12.12.2025)
Rockville Centre is located in New York, United States within 40° 39' 51.48" N -74° 21' 42.12" W (40.6643, -73.6383) coordinates. The local time in Rockville Centre is 14:45 (12.12.2025)
The calculated flying distance from Rockville Centre to Rockville Centre is 4,199.54 miles which is equal to 6,758.50 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Rockville Centre, New York, United States