Distance from Aleksandrow Lodzki to Roosevelt
The shortest distance (air line) between Aleksandrow Lodzki and Roosevelt is 4,196.76 mi (6,754.04 km).
How far is Aleksandrow Lodzki from Roosevelt
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 15:28 (13.12.2025)
Roosevelt is located in New York, United States within 40° 40' 46.92" N -74° 24' 58.68" W (40.6797, -73.5837) coordinates. The local time in Roosevelt is 09:28 (13.12.2025)
The calculated flying distance from Roosevelt to Roosevelt is 4,196.76 miles which is equal to 6,754.04 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Roosevelt, New York, United States