Distance from Aleksandrow Lodzki to Rosedale
The shortest distance (air line) between Aleksandrow Lodzki and Rosedale is 4,371.75 mi (7,035.65 km).
How far is Aleksandrow Lodzki from Rosedale
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 16:41 (13.12.2025)
Rosedale is located in Maryland, United States within 39° 19' 35.76" N -77° 29' 29.76" W (39.3266, -76.5084) coordinates. The local time in Rosedale is 10:41 (13.12.2025)
The calculated flying distance from Rosedale to Rosedale is 4,371.75 miles which is equal to 7,035.65 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Rosedale, Maryland, United States