Distance from Aleksandrow Lodzki to Roselle Park
The shortest distance (air line) between Aleksandrow Lodzki and Roselle Park is 4,222.74 mi (6,795.84 km).
How far is Aleksandrow Lodzki from Roselle Park
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 15:29 (13.12.2025)
Roselle Park is located in New Jersey, United States within 40° 39' 55.08" N -75° 44' 0.24" W (40.6653, -74.2666) coordinates. The local time in Roselle Park is 09:29 (13.12.2025)
The calculated flying distance from Roselle Park to Roselle Park is 4,222.74 miles which is equal to 6,795.84 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Roselle Park, New Jersey, United States