Distance from Aleksandrow Lodzki to Rosenberg
The shortest distance (air line) between Aleksandrow Lodzki and Rosenberg is 5,585.14 mi (8,988.42 km).
How far is Aleksandrow Lodzki from Rosenberg
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 14:34 (13.12.2025)
Rosenberg is located in Texas, United States within 29° 32' 44.16" N -96° 10' 39.72" W (29.5456, -95.8223) coordinates. The local time in Rosenberg is 07:34 (13.12.2025)
The calculated flying distance from Rosenberg to Rosenberg is 5,585.14 miles which is equal to 8,988.42 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Rosenberg, Texas, United States