Distance from Aleksandrow Lodzki to Roseville
The shortest distance (air line) between Aleksandrow Lodzki and Roseville is 5,743.41 mi (9,243.13 km).
How far is Aleksandrow Lodzki from Roseville
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 14:38 (13.12.2025)
Roseville is located in California, United States within 38° 46' 13.08" N -122° 40' 49.44" W (38.7703, -121.3196) coordinates. The local time in Roseville is 05:38 (13.12.2025)
The calculated flying distance from Roseville to Roseville is 5,743.41 miles which is equal to 9,243.13 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Roseville, California, United States