Distance from Aleksandrow Lodzki to Ruskin
The shortest distance (air line) between Aleksandrow Lodzki and Ruskin is 5,200.65 mi (8,369.64 km).
How far is Aleksandrow Lodzki from Ruskin
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 13:50 (13.12.2025)
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 07:50 (13.12.2025)
The calculated flying distance from Ruskin to Ruskin is 5,200.65 miles which is equal to 8,369.64 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Ruskin, Florida, United States