Distance from Aleksandrow Lodzki to Saginaw
The shortest distance (air line) between Aleksandrow Lodzki and Saginaw is 4,426.43 mi (7,123.66 km).
How far is Aleksandrow Lodzki from Saginaw
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 01:01 (13.12.2025)
Saginaw is located in Michigan, United States within 43° 25' 11.64" N -84° 2' 59.64" W (43.4199, -83.9501) coordinates. The local time in Saginaw is 19:01 (12.12.2025)
The calculated flying distance from Saginaw to Saginaw is 4,426.43 miles which is equal to 7,123.66 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Saginaw, Michigan, United States