Distance from Aleksandrow Lodzki to Saks
The shortest distance (air line) between Aleksandrow Lodzki and Saks is 5,004.59 mi (8,054.12 km).
How far is Aleksandrow Lodzki from Saks
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 01:01 (13.12.2025)
Saks is located in Alabama, United States within 33° 42' 42.48" N -86° 8' 47.04" W (33.7118, -85.8536) coordinates. The local time in Saks is 18:01 (12.12.2025)
The calculated flying distance from Saks to Saks is 5,004.59 miles which is equal to 8,054.12 km.
Aleksandrow Lodzki, Łódzki, Poland