Distance from Aleksandrow Lodzki to Salisbury
The shortest distance (air line) between Aleksandrow Lodzki and Salisbury is 906.67 mi (1,459.15 km).
How far is Aleksandrow Lodzki from Salisbury
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 01:00 (13.12.2025)
Salisbury is located in Wiltshire CC, United Kingdom within 51° 4' 12" N -2° 12' 36" W (51.0700, -1.7900) coordinates. The local time in Salisbury is 00:00 (13.12.2025)
The calculated flying distance from Salisbury to Salisbury is 906.67 miles which is equal to 1,459.15 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Salisbury, Wiltshire CC, United Kingdom