Distance from Aleksandrow Lodzki to San Benito
The shortest distance (air line) between Aleksandrow Lodzki and San Benito is 5,842.99 mi (9,403.38 km).
How far is Aleksandrow Lodzki from San Benito
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 03:44 (15.12.2025)
San Benito is located in Texas, United States within 26° 7' 47.28" N -98° 21' 21.6" W (26.1298, -97.6440) coordinates. The local time in San Benito is 20:44 (14.12.2025)
The calculated flying distance from San Benito to San Benito is 5,842.99 miles which is equal to 9,403.38 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
San Benito, Texas, United States