Distance from Aleksandrow Lodzki to San Clemente
The shortest distance (air line) between Aleksandrow Lodzki and San Clemente is 5,994.17 mi (9,646.68 km).
How far is Aleksandrow Lodzki from San Clemente
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 03:40 (15.12.2025)
San Clemente is located in California, United States within 33° 26' 59.64" N -118° 23' 23.28" W (33.4499, -117.6102) coordinates. The local time in San Clemente is 18:40 (14.12.2025)
The calculated flying distance from San Clemente to San Clemente is 5,994.17 miles which is equal to 9,646.68 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
San Clemente, California, United States