Distance from Aleksandrow Lodzki to San Jacinto
The shortest distance (air line) between Aleksandrow Lodzki and San Jacinto is 5,957.32 mi (9,587.38 km).
How far is Aleksandrow Lodzki from San Jacinto
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 03:40 (15.12.2025)
San Jacinto is located in California, United States within 33° 47' 49.2" N -117° 0' 30.24" W (33.7970, -116.9916) coordinates. The local time in San Jacinto is 18:40 (14.12.2025)
The calculated flying distance from San Jacinto to San Jacinto is 5,957.32 miles which is equal to 9,587.38 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
San Jacinto, California, United States