Distance from Aleksandrow Lodzki to San Jose
The shortest distance (air line) between Aleksandrow Lodzki and San Jose is 5,848.06 mi (9,411.55 km).
How far is Aleksandrow Lodzki from San Jose
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 03:39 (15.12.2025)
San Jose is located in California, United States within 37° 18' 4.32" N -122° 9' 7.2" W (37.3012, -121.8480) coordinates. The local time in San Jose is 18:39 (14.12.2025)
The calculated flying distance from San Jose to San Jose is 5,848.06 miles which is equal to 9,411.55 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
San Jose, California, United States