Distance from Aleksandrow Lodzki to San Leandro
The shortest distance (air line) between Aleksandrow Lodzki and San Leandro is 5,828.83 mi (9,380.60 km).
How far is Aleksandrow Lodzki from San Leandro
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 03:40 (15.12.2025)
San Leandro is located in California, United States within 37° 42' 26.64" N -123° 50' 24.36" W (37.7074, -122.1599) coordinates. The local time in San Leandro is 18:40 (14.12.2025)
The calculated flying distance from San Leandro to San Leandro is 5,828.83 miles which is equal to 9,380.60 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
San Leandro, California, United States