Distance from Aleksandrow Lodzki to Sarasota
The shortest distance (air line) between Aleksandrow Lodzki and Sarasota is 5,225.17 mi (8,409.10 km).
How far is Aleksandrow Lodzki from Sarasota
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 13:53 (16.12.2025)
Sarasota is located in Florida, United States within 27° 20' 19.32" N -83° 27' 24.48" W (27.3387, -82.5432) coordinates. The local time in Sarasota is 07:53 (16.12.2025)
The calculated flying distance from Sarasota to Sarasota is 5,225.17 miles which is equal to 8,409.10 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Sarasota, Florida, United States