Distance from Aleksandrow Lodzki to Sauk Rapids
The shortest distance (air line) between Aleksandrow Lodzki and Sauk Rapids is 4,634.82 mi (7,459.02 km).
How far is Aleksandrow Lodzki from Sauk Rapids
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 00:12 (16.12.2025)
Sauk Rapids is located in Minnesota, United States within 45° 35' 53.16" N -95° 50' 46.32" W (45.5981, -94.1538) coordinates. The local time in Sauk Rapids is 17:12 (15.12.2025)
The calculated flying distance from Sauk Rapids to Sauk Rapids is 4,634.82 miles which is equal to 7,459.02 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Sauk Rapids, Minnesota, United States