Distance from Aleksandrow Lodzki to Savannah
The shortest distance (air line) between Aleksandrow Lodzki and Savannah is 4,922.60 mi (7,922.17 km).
How far is Aleksandrow Lodzki from Savannah
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 07:09 (16.12.2025)
Savannah is located in Georgia, United States within 32° 1' 42.96" N -82° 49' 4.44" W (32.0286, -81.1821) coordinates. The local time in Savannah is 01:09 (16.12.2025)
The calculated flying distance from Savannah to Savannah is 4,922.60 miles which is equal to 7,922.17 km.
Aleksandrow Lodzki, Łódzki, Poland
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Savannah, Georgia, United States