Distance from Aleksandrow Lodzki to Seminole
The shortest distance (air line) between Aleksandrow Lodzki and Seminole is 5,207.14 mi (8,380.09 km).
How far is Aleksandrow Lodzki from Seminole
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 14:56 (16.12.2025)
Seminole is located in Florida, United States within 27° 50' 36.6" N -83° 12' 57.6" W (27.8435, -82.7840) coordinates. The local time in Seminole is 08:56 (16.12.2025)
The calculated flying distance from Seminole to Seminole is 5,207.14 miles which is equal to 8,380.09 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Seminole, Florida, United States