Distance from Aleksandrow Lodzki to Severna Park
The shortest distance (air line) between Aleksandrow Lodzki and Severna Park is 4,385.98 mi (7,058.56 km).
How far is Aleksandrow Lodzki from Severna Park
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 07:09 (16.12.2025)
Severna Park is located in Maryland, United States within 39° 5' 13.2" N -77° 25' 52.68" W (39.0870, -76.5687) coordinates. The local time in Severna Park is 01:09 (16.12.2025)
The calculated flying distance from Severna Park to Severna Park is 4,385.98 miles which is equal to 7,058.56 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Severna Park, Maryland, United States