Distance from Aleksandrow Lodzki to Shakopee
The shortest distance (air line) between Aleksandrow Lodzki and Shakopee is 4,659.32 mi (7,498.45 km).
How far is Aleksandrow Lodzki from Shakopee
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 19:05 (16.12.2025)
Shakopee is located in Minnesota, United States within 44° 46' 28.2" N -94° 31' 22.08" W (44.7745, -93.4772) coordinates. The local time in Shakopee is 12:05 (16.12.2025)
The calculated flying distance from Shakopee to Shakopee is 4,659.32 miles which is equal to 7,498.45 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Shakopee, Minnesota, United States