Distance from Aleksandrow Lodzki to Shawnee
The shortest distance (air line) between Aleksandrow Lodzki and Shawnee is 5,017.77 mi (8,075.33 km).
How far is Aleksandrow Lodzki from Shawnee
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 21:07 (18.12.2025)
Shawnee is located in Kansas, United States within 39° 0' 56.88" N -95° 11' 32.64" W (39.0158, -94.8076) coordinates. The local time in Shawnee is 14:07 (18.12.2025)
The calculated flying distance from Shawnee to Shawnee is 5,017.77 miles which is equal to 8,075.33 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Shawnee, Kansas, United States