Distance from Aleksandrow Lodzki to Shelby
The shortest distance (air line) between Aleksandrow Lodzki and Shelby is 4,764.08 mi (7,667.04 km).
How far is Aleksandrow Lodzki from Shelby
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 19:05 (16.12.2025)
Shelby is located in North Carolina, United States within 35° 17' 25.44" N -82° 27' 17.64" W (35.2904, -81.5451) coordinates. The local time in Shelby is 13:05 (16.12.2025)
The calculated flying distance from Shelby to Shelby is 4,764.08 miles which is equal to 7,667.04 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Shelby, North Carolina, United States