Distance from Aleksandrow Lodzki to Shively
The shortest distance (air line) between Aleksandrow Lodzki and Shively is 4,763.13 mi (7,665.52 km).
How far is Aleksandrow Lodzki from Shively
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 23:20 (16.12.2025)
Shively is located in Kentucky, United States within 38° 11' 49.2" N -86° 11' 11.04" W (38.1970, -85.8136) coordinates. The local time in Shively is 17:20 (16.12.2025)
The calculated flying distance from Shively to Shively is 4,763.13 miles which is equal to 7,665.52 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Shively, Kentucky, United States