Distance from Aleksandrow Lodzki to Sint-Andries
The shortest distance (air line) between Aleksandrow Lodzki and Sint-Andries is 693.12 mi (1,115.48 km).
How far is Aleksandrow Lodzki from Sint-Andries
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 18:34 (18.11.2024)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 18:34 (18.11.2024)
The calculated flying distance from Sint-Andries to Sint-Andries is 693.12 miles which is equal to 1,115.48 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Sint-Andries, Arr. Brugge, Belgium