Distance from Aleksandrow Lodzki to Sint-Kruis
The shortest distance (air line) between Aleksandrow Lodzki and Sint-Kruis is 690.14 mi (1,110.67 km).
How far is Aleksandrow Lodzki from Sint-Kruis
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 18:52 (18.11.2024)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 18:52 (18.11.2024)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 690.14 miles which is equal to 1,110.67 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Sint-Kruis, Arr. Brugge, Belgium