Distance from Aleksandrow Lodzki to Snellville
The shortest distance (air line) between Aleksandrow Lodzki and Snellville is 4,929.89 mi (7,933.89 km).
How far is Aleksandrow Lodzki from Snellville
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 23:36 (16.12.2025)
Snellville is located in Georgia, United States within 33° 51' 22.32" N -85° 59' 46.32" W (33.8562, -84.0038) coordinates. The local time in Snellville is 17:36 (16.12.2025)
The calculated flying distance from Snellville to Snellville is 4,929.89 miles which is equal to 7,933.89 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Snellville, Georgia, United States