Distance from Aleksandrow Lodzki to Springville
The shortest distance (air line) between Aleksandrow Lodzki and Springville is 5,431.17 mi (8,740.62 km).
How far is Aleksandrow Lodzki from Springville
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 09:24 (18.12.2025)
Springville is located in Utah, United States within 40° 9' 49.68" N -112° 22' 46.2" W (40.1638, -111.6205) coordinates. The local time in Springville is 01:24 (18.12.2025)
The calculated flying distance from Springville to Springville is 5,431.17 miles which is equal to 8,740.62 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Springville, Utah, United States