Distance from Aleksandrow Lodzki to Strongsville
The shortest distance (air line) between Aleksandrow Lodzki and Strongsville is 4,461.96 mi (7,180.83 km).
How far is Aleksandrow Lodzki from Strongsville
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 01:22 (19.12.2025)
Strongsville is located in Ohio, United States within 41° 18' 46.08" N -82° 10' 7.32" W (41.3128, -81.8313) coordinates. The local time in Strongsville is 19:22 (18.12.2025)
The calculated flying distance from Strongsville to Strongsville is 4,461.96 miles which is equal to 7,180.83 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Strongsville, Ohio, United States