Distance from Aleksandrow Lodzki to Suffolk
The shortest distance (air line) between Aleksandrow Lodzki and Suffolk is 4,509.48 mi (7,257.31 km).
How far is Aleksandrow Lodzki from Suffolk
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 01:05 (19.12.2025)
Suffolk is located in Virginia, United States within 36° 41' 43.08" N -77° 21' 36.72" W (36.6953, -76.6398) coordinates. The local time in Suffolk is 19:05 (18.12.2025)
The calculated flying distance from Suffolk to Suffolk is 4,509.48 miles which is equal to 7,257.31 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Suffolk, Virginia, United States