Distance from Aleksandrow Lodzki to Summerlin South
The shortest distance (air line) between Aleksandrow Lodzki and Summerlin South is 5,771.67 mi (9,288.60 km).
How far is Aleksandrow Lodzki from Summerlin South
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 14:36 (04.01.2026)
Summerlin South is located in Nevada, United States within 36° 7' 27.12" N -116° 40' 3.36" W (36.1242, -115.3324) coordinates. The local time in Summerlin South is 05:36 (04.01.2026)
The calculated flying distance from Summerlin South to Summerlin South is 5,771.67 miles which is equal to 9,288.60 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Summerlin South, Nevada, United States