Distance from Aleksandrow Lodzki to Terre Haute
The shortest distance (air line) between Aleksandrow Lodzki and Terre Haute is 4,749.15 mi (7,643.02 km).
How far is Aleksandrow Lodzki from Terre Haute
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 06:49 (14.01.2026)
Terre Haute is located in Indiana, United States within 39° 27' 57.6" N -88° 37' 29.64" W (39.4660, -87.3751) coordinates. The local time in Terre Haute is 00:49 (14.01.2026)
The calculated flying distance from Terre Haute to Terre Haute is 4,749.15 miles which is equal to 7,643.02 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Terre Haute, Indiana, United States