Distance from Aleksandrow Lodzki to The Hills
The shortest distance (air line) between Aleksandrow Lodzki and The Hills is 4,236.28 mi (6,817.63 km).
How far is Aleksandrow Lodzki from The Hills
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 02:03 (14.01.2026)
The Hills is located in New Jersey, United States within 40° 39' 21.96" N -75° 22' 42.6" W (40.6561, -74.6215) coordinates. The local time in The Hills is 20:03 (13.01.2026)
The calculated flying distance from The Hills to The Hills is 4,236.28 miles which is equal to 6,817.63 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
The Hills, New Jersey, United States