Distance from Aleksandrow Lodzki to Thibodaux
The shortest distance (air line) between Aleksandrow Lodzki and Thibodaux is 5,396.68 mi (8,685.12 km).
How far is Aleksandrow Lodzki from Thibodaux
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 09:46 (03.01.2026)
Thibodaux is located in Louisiana, United States within 29° 47' 41.64" N -91° 11' 7.44" W (29.7949, -90.8146) coordinates. The local time in Thibodaux is 02:46 (03.01.2026)
The calculated flying distance from Thibodaux to Thibodaux is 5,396.68 miles which is equal to 8,685.12 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Thibodaux, Louisiana, United States