Distance from Aleksandrow Lodzki to Three Lakes
The shortest distance (air line) between Aleksandrow Lodzki and Three Lakes is 5,233.50 mi (8,422.51 km).
How far is Aleksandrow Lodzki from Three Lakes
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 17:07 (19.12.2025)
Three Lakes is located in Florida, United States within 25° 38' 29.4" N -81° 35' 60" W (25.6415, -80.4000) coordinates. The local time in Three Lakes is 11:07 (19.12.2025)
The calculated flying distance from Three Lakes to Three Lakes is 5,233.50 miles which is equal to 8,422.51 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Three Lakes, Florida, United States