Distance from Aleksandrow Lodzki to Timberlake
The shortest distance (air line) between Aleksandrow Lodzki and Timberlake is 4,574.50 mi (7,361.95 km).
How far is Aleksandrow Lodzki from Timberlake
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 05:09 (09.01.2026)
Timberlake is located in Virginia, United States within 37° 19' 0.12" N -80° 45' 6.84" W (37.3167, -79.2481) coordinates. The local time in Timberlake is 23:09 (08.01.2026)
The calculated flying distance from Timberlake to Timberlake is 4,574.50 miles which is equal to 7,361.95 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Timberlake, Virginia, United States