Distance from Aleksandrow Lodzki to Trussville
The shortest distance (air line) between Aleksandrow Lodzki and Trussville is 5,034.56 mi (8,102.34 km).
How far is Aleksandrow Lodzki from Trussville
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 16:35 (03.01.2026)
Trussville is located in Alabama, United States within 33° 38' 25.8" N -87° 25' 6.6" W (33.6405, -86.5815) coordinates. The local time in Trussville is 09:35 (03.01.2026)
The calculated flying distance from Trussville to Trussville is 5,034.56 miles which is equal to 8,102.34 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Trussville, Alabama, United States