Distance from Aleksandrow Lodzki to Waterbury
The shortest distance (air line) between Aleksandrow Lodzki and Waterbury is 4,133.81 mi (6,652.73 km).
How far is Aleksandrow Lodzki from Waterbury
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 11:11 (25.12.2025)
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 05:11 (25.12.2025)
The calculated flying distance from Waterbury to Waterbury is 4,133.81 miles which is equal to 6,652.73 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Waterbury, Connecticut, United States