Distance from Aleksandrow Lodzki to Waukegan
The shortest distance (air line) between Aleksandrow Lodzki and Waukegan is 4,611.39 mi (7,421.32 km).
How far is Aleksandrow Lodzki from Waukegan
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 14:11 (07.01.2026)
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 07:11 (07.01.2026)
The calculated flying distance from Waukegan to Waukegan is 4,611.39 miles which is equal to 7,421.32 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Waukegan, Illinois, United States