Distance from Aleksandrow Lodzki to Waukesha
The shortest distance (air line) between Aleksandrow Lodzki and Waukesha is 4,589.82 mi (7,386.60 km).
How far is Aleksandrow Lodzki from Waukesha
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 06:58 (04.01.2026)
Waukesha is located in Wisconsin, United States within 43° 0' 31.32" N -89° 45' 12.96" W (43.0087, -88.2464) coordinates. The local time in Waukesha is 23:58 (03.01.2026)
The calculated flying distance from Waukesha to Waukesha is 4,589.82 miles which is equal to 7,386.60 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Waukesha, Wisconsin, United States